Given two lists of closed intervals, each list of intervals is pairwise disjoint and in sorted order.
Return the intersection of these two interval lists.
(Formally, a closed interval [a, b] (with a <= b) denotes the set of real numbers x with a <= x <= b. The intersection of two closed intervals is a set of real numbers that is either empty, or can be represented as a closed interval. For example, the intersection of [1, 3] and [2, 4] is [2, 3].)
Example 1:
Input: A = [[0,2],[5,10],[13,23],[24,25]], B = [[1,5],[8,12],[15,24],[25,26]]
Output: [[1,2],[5,5],[8,10],[15,23],[24,24],[25,25]]
Reminder: The inputs and the desired output are lists of Interval objects, and not arrays or lists.
class Solution:
def intervalListIntersection(self, A, B):
ans = []
i = j = 0
while i < len(A) and j < len(B):
left = max(A[i][0], B[j][0])
right = min(A[i][1], B[j][1])
if left <= right:
ans.append([left, right])
if A[i][1] < B[j][1]:
i += 1
else:
j += 1
return ans