Problem
Given a set of candidate numbers (candidates) (without duplicates) and a target number (target),
find all unique combinations in candidates where the candidate numbers sums to target.
The same repeated number may be chosen from candidates unlimited number of times.
Note:
All numbers (including target) will be positive integers.
The solution set must not contain duplicate combinations.
Example 1:
Input: candidates = [2,3,6,7], target = 7,
A solution set is:
[
[7],
[2,2,3]
]
Example 2:
Input: candidates = [2,3,5], target = 8,
A solution set is:
[
[2,2,2,2],
[2,3,3],
[3,5]
]
Solution
Backtracking problem.
See Problem 40.
class Solution:
def combinationSum(self, candidates, target):
self.ans = []
self.dfs(sorted(candidates), 0, [], target)
return self.ans
def dfs(self, candidates, index, path, target):
if target == 0:
self.ans.append(list(path))
for i in range(index, len(candidates)):
v = candidates[i]
if v > target:
return
path.append(v)
self.dfs(candidates, i, path, target-v)
path.pop()