You have n tiles, where each tile has one letter tiles[i] printed on it.
Return the number of possible non-empty sequences of letters you can make using the letters printed on those tiles.
Example 1:
Input: tiles = "AAB"
Output: 8
Explanation: The possible sequences are "A", "B", "AA", "AB", "BA", "AAB", "ABA", "BAA".
Example 2:
Input: tiles = "AAABBC"
Output: 188
Example 3:
Input: tiles = "V"
Output: 1
Constraints:
1 <= tiles.length <= 7
tiles consists of uppercase English letters.
class Solution:
def numTilePossibilities(self, tiles: str) -> int:
self.ans = 0
mark = [False] * len(tiles)
self.dfs(sorted(tiles), mark)
return self.ans
def dfs(self, tiles, mark):
for i in range(len(tiles)):
if mark[i] or (i > 0 and tiles[i] == tiles[i-1] and not mark[i-1]):
continue
mark[i] = True
self.ans += 1
self.dfs(tiles, mark)
mark[i] = False